Calendar Questions For Competitive Exams
Q-6. If 8th Feb 2005 it was Tuesday then what was the day of the week on 8 Feb 2004?
a) Sunday
b) Tuesday
c) Monday
d) Wednesday
Answer :(a) Sunday
Solution:
The year 2004 is a leap year. it has 2 odd days.
The day on 8th Feb 2004 is 2 days before the day on 8th Feb 2005.
Hence, this day is Sunday.
Q-7. What day will be the day of the week 15th August 2010?
a) Sunday
b) Tuesday
c) Monday
d) Friday
Answer :(a) Sunday
Solution:
15th August 2010
= (9 yrs + period 1/01/2010 to 15/08/2010)
What type in 1600 years= 0
odd days in 100 years= 0
9 yrs= (2 Leap years + 7 ordinary years)
= (2 x 2 +7 x1)
=11 days it means 4 odd days.
Jan Feb Mar Apr May Jun Jul Aug.
(31+28+31+30+31+30+31+15)
=277 days
means (32 weeks + 3 days)
= 3 odd days
Total number of odd days
= (0+0+4+3)
= 7 (zero odd days)
Given day is sunday
Q-8. What was the day of the week on 28th May 2006?
a) Thursday
b) Tuesday
c) Sunday
d) Friday
Answer :(c) Sunday
Solution:
28 May, 2006
=(2005 years + period from 1/01/2006 to 28/05/2006)
Odd days in 1600 years= 0
Odd days in in 400 years= 0
5 years=( 4 ordinary years+ 1 leap years)
= (4 x 1 + 1 x 2)
= 6 odd days
Jan Feb Mar Apr May
(31+28+31+30+28)
= 148 days
Means (21 weeks + 1 day) 1 odd day.
Total number of odd days
= (0+0+6+1)= 7 days
It means 0 odd days
Given day is sunday
Q-9. What was the day of the week on 17th June 1998?
a) Thursday
b) Wednesday
c) Sunday
d) Friday
Answer :(b) Wednesday
Solution:
17th June, 1998
=( 1997 years + period from 1/01/1998 to 17/06/1998)
Odd days in in 1600 years= 0
Odd days in 300 years
= (5x3)= 15 = 1 odd day
97 Years has 24 leap years+ 73 ordinary years.
Number of odd days in 97 years
=(24 x 2 + 73)
= 121= 2 odd days
Jan Feb Mar Apr May Jun
(31+28+31+30+31+17)
=168 days
Means 24 weeks = 0 odd days
So, total no. od odd days
= (0+1+2+0)= 3
One day is Wednesday
Q-10. On what dates of April 2001 did Wednesday fall?
a) 1st, 8th, 15th, 22nd, 29th
b) 3rd, 10th, 17th, 24th
c) 2nd, 9th, 16th, 23rd, 30th
d) 4th, 11th, 18th, 25th
Answer :(d) 4th, 11th, 18th, 25th
Solution:
We shall find the day on 1st April, 2001.
1st April 2001
=(2000 years + period from 1/01/2001 to 1/04/2001)
Odd days in 1600 in years= 0
Odd days in 400 years= 0
Jan Feb Mar Apr
(31+28+31+1)
= 91 days = 0 odd days
Total number of odd days
= (0+0+0)= 0
on 1st April 2001 it was Sunday.
In April 2001 Wednesday Falls on
4th, 11th, 18th, and 25th.
About the author
Hi,
I am Vaibhav Choudhary, Reasoning Teacher by Profession but Blogger by a passion. I would like to share my reasoning knowledge with students those are taking a preparation of government exam or competitive exam.
