50+ Clock Reasoning Questions and Answers
Clock Reasoning Questions – Hard Level
Q-31. The minute hand of a clock overtakes the hour hand at intervals of 66 minute of correct time. How much a day does the clock gain or lose?
(a) 11[latex]\frac{109}{121}[/latex] minute gain
(b) 11[latex]\frac{109}{121}[/latex] minute loss
(c) 11[latex]\frac{117}{121}[/latex] minute gain
(d) 11[latex]\frac{117}{121}[/latex] minute loss
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Answer: (b) 11[latex]\frac{109}{121}[/latex] minute loss
Solution:
Total loses in 66 minutes is
= 66 - 65 [latex]\frac{5}{11}[/latex]
= 66- [latex]\frac{720}{11}[/latex]
= [latex]\frac{726 - 720}{11}[/latex] = [latex]\frac{6}{11}[/latex]
In 1 minutes
=[latex]\frac{6}{11\times 6}[/latex]
In 24 × 60 Minute
=[latex]\frac{6\times 24\times 60}{11\times 6}[/latex]
= [latex]\frac{1440}{121}[/latex]
=11 [latex]\frac{109}{121}[/latex]minutes loss
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Q-32. A clock is set right at 8 a.m. on sunday. It gains 8 minutes in 24 houus. What is the correct time when the clock indicates 9 p.m. on upcoming sunday?
(a) 9 P.M (b) 8:30 P.M
(c) 8 P.M (d) 10 P.M
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Answer: (c) 8 P.M
Solution:
Total hours form 8 a.m. Sunday to 9 p.m. following sunday = 181 hours
24 hours + 8 minutes
24+[latex]\frac{8}{60}[/latex]= 24+[latex]\frac{2}{15}[/latex]
= [latex]\frac{360+2}{15} [/latex] hours
[latex]\frac{362}{15}[/latex]hours of this clock
⇒ 24 hours of correct clock
1 hours of this clock = 24 ×[latex]\frac{15}{362}[/latex]hour of correct clock
181 hour of this clock
=[latex]\frac{24\times 15\times 181}{362}[/latex]
=180 hours of correct clock
The correct time would be:
9pm - 1 hour = 8p.m
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Q-33. A clock is set right at 10 A.M on sunday. It loses 8 minutes in 24 hours. What is the correct time when the clock indicates 9 P.M on next sunday?
(a) 9 P.M (b) 9 A.M
(c) 10 A.M (d) 10 P.M
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Answer: (d) 10 P.M
Solution:
Total hours of clock from 10 - A.M Sunday to 9 P.M on following Sunday = 179 hours
24 hour - 8 minutes = 23 hour 52 minutes
23+[latex]\frac{52}{60}[/latex]
=[latex] \frac{345+13}{15}= \frac{358}{15}[/latex] hr.
[latex]\frac{358}{15}[/latex] hours of this clock = 24 hour of correct clock
1 hour of this clock = 24 ×[latex]\frac{15}{358}[/latex]hour of correct clock
179 hour of this clock
=[latex]\frac{24\times 15\times 179}{358}[/latex]
= 180 hour of correct clock.
The correct time would be = 9
p.m. +1 hour = 10 p.m.
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Q-34. A watch which gains uniformaly is 4 minute slow at 9 A.M on Sunday, and is 4 minute 15 sec. fast at 9P.M on upcoming Friday. When was it correct?
(a) 2 A.M Thursday (b) 6 P.M Wednesday
(c) 1 A.M Wednesday (d) 6P.M
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Answer: (c) 1 A.M Wednesday
Solution:
Sunday 9 A. M
Upcoming Friday 9 P.M
= 4 minute 4 Minute 15 sec.
Total gains = 8 min 15 sec
=8+[latex]\frac{15}{60}[/latex]
= 8+[latex]\frac{1}{4}[/latex]
=[latex]\frac{33}{4}[/latex]min
Total hours = 5 days + 12 hr.
= 120 + 12 = 132 hours
[latex]\frac{33}{4}[/latex] min. gains in = 132 hour
1 minute gains in
= [latex]\frac{132}{33}[/latex] x 4
4 minute gain in
= [latex]\frac{132}{33}[/latex] x 4 x 4 = 64 hour
9 A.M Sunday + 64 hours
9 A.M Sunday + 2 dyas 16 hours = 1 A.M Wednesday
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Q-35. A watch which loses uniformaly is 3 minute fast at 6 A.M on Thursday and is 3 minute 12 sec. slow at 5 P.M on upcoming wednesday. When was it correct?
(a) 9 P.M on Sunday
(b) 9 A.M on Monday
(c) 9 A.M on Sunday
(d) 8 A.M on Sunday
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Answer: (c) 9 A.M on Sunday
Solution:
6 A.M Thursday 5 P.M upcorning Wednesday +3 minutes - (3 minutes + 12 sec.)
Total loses = 6 min. + 12 sec
=6+[latex]\frac{12}{60}[/latex]
= 6+[latex]\frac{1}{5}[/latex]
=[latex]\frac{31}{5}[/latex]min
Total hour = 6 days + 11hour
=24×6+11=144+11=155 hour
[latex]\frac{31}{5}[/latex]minutes lose in = 155 hr.
1 minutes lose in = [latex]\frac{155}{31}[/latex] x 5
3 minutes lose in = [latex]\frac{155}{31}[/latex] x 5 x 3
= 75 hour
75 hour = 3 day + 3 hour
So, Thursday 6 A.M+ (3 day +3 hour)
= Sunday 9 A.M
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