50+ Clock Reasoning Questions and Answers

March 30, 2024May 21, 2023 by vaibhav

Clock Reasoning Questions and Answers

Q-41. A clock with only dots marking 3, 6, 9 and 12 positions has been kept upside down in front of a mirror. A person reads the time in the reflection as 9.50. What is the actual time?
(a) 2 : 15 (b) 8 : 40
(c) 8 : 50 (d) 4:15

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Answer: (b) 8 : 40
Solution:
In this question reflection works as water image
(Image)
In this time 9 : 50 the both hand of clock are lies be- tween 6 to 12 clockwise. Hence we subtract that time from 17 : 90
17:90 -  9:50 = 8:40
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Q-42. A clock with only dots marking 3, 6, 9, and 12 positions has been upside down in front of a mirror. A person reads the time in the reflection as 6 : 10 The real time is:
(a) 06 : 15 (b) 8 : 40
(c) 11 : 20 (d) 7:15

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Answer: (c) 11 : 20
Solution:
In this time 6 : 10 the hour hand lies between 6 : 00 to 12:00 clockwise and hour hand lies between 12 : 00 to 600. Hence we subtract that time from 17 : 30
17:30 - 6:10 = 11: 20
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Q-43. At what time between 5:00 to 6:00 O’  clock ok both hands of the clock from the right angle of the second time
a) [latex] 43\frac{5}{11} [/latex]
b) [latex] 43\frac{7}{11} [/latex]
c) 40 min past 5
d) 45 min past 5

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Answer: (b)
Solution:
Two right angle  formed in one hour
at 5 o'clock,  the hands are 25 min space apart.
two from right angle for the second time between  5:00 to 6:00, The minute hand has to gain (25+15)= 40 min. Space as in 1 min
=[latex]\frac{12}{11}[/latex]min.gain 
   Therefore in in 40 minute
=[latex]\frac{12}{11}\times40 [/latex]
=[latex]43\frac{7}{11}[/latex]min 
Hence Required time  [latex] =43\frac{7}{11}[/latex]min past 5
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Q-44. At what time between 6:00 to 7:00 o’clock both hands of the clock coincide? 

a) [latex] 33\frac{7}{11} [/latex] min past 6

b) [latex] 32\frac{8}{11} [/latex] min past 6

c) [latex] 34\frac{6}{11} [/latex] min past 6

d) [latex] 328\frac{2}{11} [/latex] min past 6

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Answer: (b) 
Solution:
coincide means 00 
At 6 o'clock,  the hands are 30 minutes space apart.

To from 00  between 6:00 to 7:00, The minute hand moves equivalent to H and.  therefore the minute hand has to move 30 minute  Space to coincide As in one minute = [latex] \frac{12}{11}[/latex] min gain
Therefore in 30 minute
= [latex]\frac{12}{11}\times30[/latex]
= [latex]32\frac{8}{11}[/latex] min
Hance required time = [latex]32\frac{8}{11}[/latex] min past 6.
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Q-45. At what time between 7:00 to 8:00 o’clock both hands of the clock be in a straight line but not together?
a) [latex] 5\frac{2}{12} [/latex]
b) 5 min past 7
c) [latex] 6\frac{4}{11} [/latex] min past 7
d) [latex] 5\frac{5}{11} [/latex] min past 7

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Answer: (d) 
Solution:
both hands of the clock be in straight line but not together means opposite i.e 1800
At 7 o'clock,  the hands are 35 min  space apart.
To from 1800 between 7:00 to 8:00, The minute hand has to gain (35-30)= 5min.
space as in 1 minute
= [latex] \frac{12}{11}[/latex] min gain.
Therefore in 5 min
= [latex]\frac{12}{11}\times5[/latex]

= [latex] 5\frac{5}{11} [/latex] min
Hence, Required time
= [latex] 5\frac{5}{11} [/latex] min past 7.
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