Arithmetic Reasoning Questions For SSC CGL

Arithmetic Reasoning Questions plays most important role in competitive exams. It deals with mathematical problems includes Ratio and proportion, Age, number series, percentage, power, time and distance etc. In this Post, we provide most important examples of Arithmetic Reasoning Questions For SSC CGL with solution that help to understand the method for solving Arithmetic Reasoning Questions And Answers.

Arithmetic Reasoning Questions For SSC CGL

Q-1.  Aniket  is 5 times older than her sister priya,  who is two years less than his brother shyam.  If  Shyam is 8 years old,  then what will be the age of Aniket?
(A) 30 years
(B) 24 years
(C) 40 years
(D) 28 years

View Answer and Solution 

Answer: (A) 30 years
Solution: 
The age of Shyam = 8 years
The age of Priya= 8-2=6 years 
The age of Aniket= 6 x 5= 30 years 

Q-2. Rakesh’s age is 10 years less than half of his mother’s age  who is 5 years younger than  Rakesh’s father. If father age is 45 years old then what is the age of Rakesh?
(A) 20 years
(B) 15 years
(C) 10 years
(D) 5 years

View Answer and Solution 

Answer: (C) 10 years
Solution: 
The age of mother
= 45-5= 40 years
The age of sun 
= \left( \frac{40}{2} \right)-10
= 10 years

Q-3.  When a man had his first son, his age was 32 years.  His wife was 35 years of age when his son attended the age of 7 years.  Find the age difference between the man and his wife ?
(A) 7 years
(B) 3 years
(C) 5 years
(D) 4 years

View Answer and Solution 

Answer: (D) 4 years
Solution: 
The age of mother, at the time of son birth
= 35- 7 = 28
So, Age Difference 
= 32-28 = 4 years

Q-4. 5 years ago Shivam’s mother was 3 times as old as Shivam. After 5 years she will be twice as old as Shivam. How old is Shivam today ?
(A) 10 years
(B) 15 years
(C) 20 years
(D) 25 years

View Answer and Solution 

Answer:(B) 15 years
Solution:
consider the present age of Shivam is x years and his mother is y years.
5 years ago
= 3 (x-5)=(y-5)
= 3x-15 = y-5
= 3x-y= 10
5 years hence,
  2 (x+5) = (y+5)
= 2x + 10 = (y+5)
= 2x - y = -5
x = 15 years

Q-5. 50 men can drill 40 holes in 30 days. Then How long will 25 men take to drill 20 holes?
(A) 15 days
(B) 22 days
(C) 30 days
(D) 45 days

View Answer and Solution 

Answer: (C) 30 days
Solution: 
\frac{MDH}{W}=\frac{MDH}{W}
50 men can drilled 40 holes in 30 days
so, 25 men can drill 20 holes in 
=\frac{30 X 50 X 20}{40 X 25}
= 30 days

Q-6.  There are some dogs and some boys at a playground. If the total number of legs is 20 and total number of heads is 7, then find how many boys and dogs are there ?
(A) 2 boys and 5 dogs
(B) 3 boys and 4 dogs
(C) 4 boys and 3 dogs
(D) 5 boys and 2 dogs

View Answer and Solution 

Answer: (C) 4 boys and 3 dogs
Solution:
Number of heads = B + D = 7 (i)
Number of legs = 2B + 4D = 20 (II)
From statements (i) and (II)
B=4 and D= 3 

Q-7. A father gives some money to his five sons as given below. Find How much money does he give to youngest son?
son. 1st    2nd   3rd   4th  5th
Rs. 145  100   64    37     ?
(A) Rs. 29
(B) Rs. 25
(C) Rs. 22
(D) Rs. 19

View Answer and Solution 

Answer: (D) Rs. 19
Solution:
The distribution of money in 5 son is based on the following pattern:
1st  = Rs. 145 
2nd= 145 - 45 (i.e. 9 x 5)
        = Rs. 100
3rd= 100-9 x 4 = Rs. 64
4th= 64 - 9 x 3 = Rs. 37
5th= 37 - 9 x 2 = Rs. 19 

Q-8.  The number of Oranges in a container  doubles every one minute. If the container is full of oranges in one hour, then when was the container filled half ? 
(A) 38 minutes
(B) 55 minutes
(C) 47 minutes
(D) 59 minutes

View Answer and Solution 

Answer: (D) 59 minutes
Solution:
In the 59th minute the basket was half-filled.