Arithmetic Reasoning Questions For Competitive Exam

Q-31. The school result is increasing year after year. Forecast the result of 2012 from the following inform-ation.

(a) 51.75% (b) 56.75%
(c) 48.00% (d) 57.25%

View Answer and Solution 
  
Answer: (b)
Solution:
34.25 +2.50 = 36.75
36.75 +3.00 = 39.75
39.75 +3.50 = 43.25
43.25 +4.00 = 47.25
47.25 +4.50 = 51.75
51.75 +5.00 = 56.75

Q-32. A person’s present age is two- fifth of the age of his mother. After 8 years, he will be one- half, of the age of his mother. How old is the mother at present?
(a) 40 years (b) 48 years
(c) 32 years (d) 36 years

View Answer and Solution 
  
Answer: (a)
Solution:
Suppose the present age of the mother = Fyears
∴ Present age of person
\frac{2}{5}F years
8 years hence
\left ( \frac{2}{5}F+8 \right )=\frac{(F+8)}{2}
or,  2\frac{(2F+40)}{5}=F+8
4x + 80 = 5x + 40
5x - 40 = 80 - 40
∴F = 40 years

Q-33. A father’s age is now three times that of his elder daughter. Five years back, his age was eight times that of his younger daughter. If the difference of ages of the two daughters is 5 years, what is the age of the father now?

(a) 55 (b) 50
(c) 60 (d) 45

View Answer and Solution 
  
Answer: (d)
Solution:
Suppose the present age of younger daughter is F years.
∴ Present age of the elder daughter
= F + 5 years.
Present age of the father
= 3 (F + 5) years.
According to the question,
8 (F - 5) = 3F + 15 - 5
8F - 40 = 3F + 10
8F - 3F = 10 + 40
F= 50/5 = 10 years
Present age of father
= 3 × (10 + 5)
= 45 years

Q-34. Neela is now three times as old as her daughter Leela. Ten years back, Neela was five times as old as Leela. The age of Leela is ?

(a) 15 (b) 25
(c) 30 (d) 20

View Answer and Solution 
  
Answer: (d)
Solution:
Suppose the present age of Leela is Fyears
Therefore, the present age Neela = 3F years
10 years ago
5 (F– 10) = (3F- 10)
5F - 50 = 3F - 10
5F - 3F = 50 - 10
2F = 40
F= 20 years