50+ Arithmetical Reasoning Questions And Answers

Arithmetical Reasoning For Competitive Exam

Q-35. 20 years ago, Antony’s age was 1 / 2 of what his age now is. What is his age now?

(a) 20 years (b) 40 years
(c) 35 years (d) 30 years

View Answer and Solution 
  
Answer: (d)
Solution:
Suppose, the present age of Antony is F years and 20 years ago his age was F/2 years.
Now,
F - 20 = F/2
2F - 40 = F
2F - F = 40
∴ F = 40 years

Q-36. A father is three times as old his son. Eight years ago, the father was five times as old as his son. What is the present age of the son?

(a) 12 years (b) 14 years
(c) 16 years (d) 20 years

View Answer and Solution 
  
Answer: (c)
Solution:
Suppose the present age of the son is F years.
Therefore, the present age of father will be 3F years
5 (F - 8) = 3F - 8
5F - 40 = 3F - 8
5F - 3F = 40 - 8
2F = 32
∴ F=32/2 = 16 years

Q-37. Amit was born 5 years before Rakesh, Rakesh is 3 years younger to Anil. If Amit is now 17 years old, how old is Anil?

(a) 8 years (b) 12 years
(c) 15 years (d) 19 years

View Answer and Solution 
  
Answer: (c)
Solution:
Amit = 17 years
Rakesh = 17 - 5 = 12 years
∴ Anil = 12 + 3 = 15 years

Q-38. A book has 300 pages and each page has 20 lines of 10 words each. How many words are there in the book altogether?

(a) 6000 (b) 60000
(c) 66000 (d) 600000

View Answer and Solution 
  
Answer: (b)
Solution:
Total number of words
300 × 20 × 10 = 60000

Q-39. The number of students in a course increases every year in a college. Find out the number in 2010 from the following information:

(a) 70 (b) 75
(c) 55 (d) 65

View Answer and Solution 
  
Answer: (b)
Solution:

Q-40. In a joint family, there are father, mother, four married sons and two unmarried daughters. Three sons have 2 daughters each and one has a son. How many female members are there in the family?

(a) 13 (b) 8
(c) 11 (d) 12

View Answer and Solution 
  
Answer: (a)
Solution:
Mother = 1
Wives = 4
Unmarried daughters = 2
Total number of female members
= 1 + 4 + 2 + 6 = 13