50+ Arithmetical Reasoning Questions And Answers

Arithmetic Reasoning For Competitive Exam

Q-41. There are twelve dozens of apples in a basket. Two dozens are added late. Ten apples got spoilt and are removed. The remaining are transferred equally into two baskets. How many are there in each?

(a) 168 (b) 158
(c) 79 (d) 89

View Answer and Solution 
  
Answer: (c)
Solution:
Total number of apples
= 14 × 12 = 168
Ten apple were removed remaining apples
= 168 - 10 = 158
Now,
158/2 = 79

Q-42. A shepherd had 34 sheep. But 16 died. How many sheep were left?

(a) 16 (b) 14
(c) 18 (d) 34

View Answer and Solution 
  
Answer: (c)
Solution:
According to question,
16 sheep died. Therefore, 18 sheep were left.

Q-43. In a double track rail route, two trains start simultaneously from the opposite stations, 200km apart. The train A runs westwards at a speed of 50 kmph and the opposite train B runs east-wards at 40km/ h. After 3 hours, what will be the distance between these two trains?

(a) 30kms (b) 50kms
(c) 80kms (d) 70 kms

View Answer and Solution 
  
Answer: (d)
Solution:
Relative speed of trains A and B
= 50 + 4 0= 90 kmph
Distance covered in 3 hours = 3 × 90 = 270 km
Distance between the two trains = 270 - 200 = 70 km

Q-44. In a platform, train ‘A’ 225m. long is stopped to allow train ‘B’ 375 m long to pass. Speed of ‘B’ is 90km per hour. Time taken by train ‘B’ to cress train ‘A’ completely will be ?

(a) 6.67 sec. (b) 9 sec.
(c) 2.5 sec. (d) 24 sec.

View Answer and Solution 
  
Answer: (d)
Solution:
Time taken by train 'B' to cross the standing train 'A' will be equal to time taken by the train 'B' to cover a total distance of (225+375) metres.
t =  \frac{225 + 375}{v} 
Speed of train B
  = 90 ×  \frac{5}{18} = 25 m/s
t =  \frac{600}{25}  = 24 sec

Q-45. Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?

(a) 9 (b) 10
(c) 12 (d) 20

View Answer and Solution 
  
Answer: (b)
Solution:
Relative speed
= (54 - 45) kmph = 9 kmph
Stoppage per hour
= \frac{9}{54}×60 
= 10 minutes